Math, asked by ruthilalramnghaki06, 3 days ago

If the equation kx square- 6x +1 -0 has real and equal roots, then the value of k is -

Answers

Answered by aliabbasshah145

0

Answer:

The given quadric equation is kx2 + 6x + 1 = 0, and roots are real and distinct. Then find the value of k. Therefore, the value of k < 9.

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