Question

if the equation kx2+(2k-3)y2-4x+6y-1=0 represent a circle then find the coordinates of its centre are​

Answer 1

Answer:

General equation of a circle is

x^ 2 +y^ 2 +2gx+2fy=c.

Where r= root of (g+f-c). Given eqns is

kx^ 2 +(2k-3)y^ 2 -4x+6y-1=0. Comparing with standard eqns we get. k= 2k-3.

or k = 3 answer