Question

If the equation kxsquare -2kx+6=0 has equal roots,then find the value of k?​

Answer 1

For equal roots b^2 - 4ac =0

Answer 2

Answer:

Step-by-step explanation:

Kx²-2kx+6=0

Therefore,

b²-4ac=0

Here,

b= -2k

a= k

c =6

ie, (-2k)²-4*k*6=0

4k²-24k=0

4k(k-6)=0

k-6=0

k=6

Hence, Value of k is 6

Hope it helps

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