If the equation mx square +2x +m=0 has two unequal roots,then find the value of m.
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plus one is not possible because it is equal to one
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Answer:
m < -1
Step-by-step explanation:
Given equation is
mx^2 + 2x + m = 0
Now we know that for unequal roots b^2 - 4ac >0
(2)^2 - 4(m)(m) > 0
4 - 4m^2> 0
4m^2 <4
m^2 < 1
m < 1 and m < -1
the common is m < -1.
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