Question

If the equation of a circle is (4a - 3) * x ^ 2 + a * y ^ 2 + 6x - 2y + 2 = 0 , then its centre is​

Answer 1

Answer:

hope this helps

Step-by-step explanation:

Given circle is

x

2

+y

2

+2hxy+2gx+2fy+c=0 (i)

For Eq. (i) to represent a circle, h = 0

∴ Given circle is

x

2

+y

2

+2gx+2fy+c=0 (ii)

For circle Eq. (ii) to pass thorough three quadrants only

i. AB>0∴g

2

−c>0

ii. CD>0∴g

2

−c>0

iii. Origin should lie outside circle Eq. (ii)

∴c>0

Therefore, required conditions are g

2

>c,f

2

>c,c>0,h=0