if the equation of a circle is ax^2+(2a-3) y^2-4x+6y-1=0 then the coordinates of center are
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ax2 + 2hxy + by2 + 2g x + 2fy + c = 0 is represent a circle 2h = 0 and a = b. If ax2 + (2a - 3)y2 - 4x + 6y - 1=0 is the equation of the circle Here a = 2a - 3 a = 3 Then 3x2 + 3y2 - 4x + 6y - 1 = 0 x2 + y2 - 4 x/ 3 + 6y / 3 - 1 / 3 = 0 Center = ( -g / a , -f / a) Center = ( 2 / 3 ,-1)
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