Math, asked by murtygaru345, 3 months ago


If the equation of the plane passing through the points (1,2,3), (-1,2,0) and perpendicular to the
ZX-plane is x + by + cz + d= 0 (a > 0) then
1) a = 0 and c = 0 2) a + d=0
3) c + d -5 =0
4) a + b +c+d 4=0




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Answers

Answered by gurbaninain9
1

Answer:

32095Hope it's help you

Step-by-step explanation:

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Answered by gargpriya0114
0

Answer:

4) a + b +c+d-4=0 .

Step-by-step explanation:

Normal to ZX plane means the point (1,0,1) .

3 points are (1,2,3) , (-1,2,0) , (1,0,1) .

If we use determinant rule to find the plane equation then the result is

3x+2y-2z-1=0.

Then a=3 , b=2 , c=-2 , d=-1 .

Therefore no option is correct here .

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