Question

if the equation (p²-1)x² -2pbx +(b²-1)=0 has equal roots, prove that b²=1-p²

Answer 1

Step-by-step explanation:

if roots are real then

b^2 -4ac =0

where the general form of the equation is ax^2+bx+c ..

Answer 2

I have attached the hand written solution you may go through it