Question

If the equation secx+cosecx=c has three real roots between 0 and pi then 1)c^2= 8 2)c^2 8 4)0

Answer 1

Answer:

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Answer 2

Answer:

c^2=8

Step-by-step explanation:

secx+cscx=C

2√2sin(X+π/4)/sin2x=C

let sin(X+π/4)/sin2x=y

for maximum or minimum value dy/dx=0

dy/dx=(1-tanx)(1+tanx+tan^2x)

tanx=1

X=45°,225°

hence there exists a maximum value at X=45°

C<= 2√2