Question

if the equation
$k x ^{2} - 2kx + 6 = 0$
has equal roots then find the value of ""k""​

Answer 1

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→ Answer :

   k = 6

→ To Find :

Value of  'k'

→ Step-by-step explanation :

Given that Quadratic equation is

$kx^2-2kx+6=0$  has equal roots.

Compare given equation $kx^2-2kx+6=0$ with

$ax^2+bx+c=0$ .Then  we get ,

$a = k , b = -2k , c = 6$

We know that , " If the equation has two equal roots ".

" Then Discriminant ( D ) = 0 "

$b^2-4ac=0\\\\=> (-2k)^2-4*(k)*6 = 0\\\\=> 4k^2-24k=0\\\\=> 4k(k-6)=0\\\\=> 4k=0 , k-6=0\\\\=> k=0 , k=6$

Here , k = 0 is not possible.

Because , If the value of k=0, just sub. this in quadratic equation and imagine.

Then the equation is not a quadratic equation.

Therefore, Value of k is 6

=> k = 6

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