If the equation x^2 + 2(k+1)x + 9k-5 = 0 has only negative roots then
(i) - k≤ 0
(ii) k≥ 0
(iii) k > 5/9
(iv) k≤6
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anshaj0001:
very good and thanks
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According to the question :-
•The equation is in the form of negative
As per :-
•Product of roots always be in positive
Therefore :-
= 9 K - 5 > 0
= 9 K > 5
= K > 5 ÷ 9
= K > 5/9
•Correct option = (3)
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
According to the question :-
•The equation is in the form of negative
As per :-
•Product of roots always be in positive
Therefore :-
= 9 K - 5 > 0
= 9 K > 5
= K > 5 ÷ 9
= K > 5/9
•Correct option = (3)
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