Question

If the equation x^2+2kx+4=0 has two equal and real roots then find k ​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Given

✭ x²+2kx+4 = 0 has equal zeros

To Find

◈ The value of k?

Solution

Concept

We shall compare the polynomial with b²-4ac = 0 to find the value of k. Because for a polynomial to have equal zeros it has to satisfy this formula

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We know that,

b²-4ac

Comparing x²+2kx+4 = 0 with ax²+bx+c = 0

◕ a = 1

◕ b = 2k

◕ c = 4

Substituting the values,

➝ b²-4ac = 0

➝ (2k)²-4 × 1 × 4 = 0

➝ 4k²-16 = 0

➝ 4k² = 16

➝ k² = 16/4

➝ k² = 4

➝ k = ±√4

➝ k = 2 or -2

☯ Know More

»» α+β = -b/a

»» αβ = c/a

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