Question

If the equation x^2+4+3cos(a+b)=2x has a solution then a possible value of a+b equal ab​

Answer 1

Answer:

$3\pi$

Step-by-step explanation:

$x^2-2x+4=-3cos(ax+b)\\(x-1)^2+3=-3cos(ax+b)$

For above equation to have at least one solution,

let $f$$(x)=(x-1)^2+3 and F(x)=-3cos(ax+b)$

If x=1 then LHS=3 and RHS=−3cos(a+b)

Hence,cos(a+b)=−1

∴a+b=π,3π,5π

But,0≤a+b≤10⇒a+b=π or 3π

Hence,$3\pi$ is the correct answer !!

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