Question

If the equation x^2 + 4x + k = 0 has real roots, then
(A) k≥4
(B) k ≤4
(C) k≥0
(C) k≤0
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Answer 1

Answer:-

(B) k≤4

Explanation:-

x²+4x+k = 0

If the equation has real roots, then

Δ ≥ 0

b² - 4ac ≥0

4² - 4(1)(k) ≥ 0

16 ≥ 4k

k≤4

Answer 2

option B..............