Question

if the equation x^2-bx+1= 0 has two distinctreal real roots then which of the following is correct .
(a) b^2-4a>0
(b) b^2-4>0
(c)b^2-4=0
(d)b^2-4c>0​

Answer 1

Answer:

b

Step-by-step explanation:

distinct and real root D>0.

D=b^2-4ac

b^2-4*1*1>0

b^2-4>0

Answer 2

Answer:

${b}^{2} - 4ac$

is the right answer.