if the equation x^2- kx+49=0 has only one root real then k=__
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Answer:
±14
Step-by-step explanation:
Given Quadratic Equation is x² - kx + 49 = 0
On comparing with ax² + bx + c = 0,
We get a = 1, b = -k, c = 49
Given that the equation has only one real root.
∴ Δ = b² - 4ac
⇒ 0 = (-k)² - 4(1)(49)
⇒ 0 = k² - 196
⇒ k² = 196
⇒ k = ±14.
Therefore, the value of k = ±14.
Hope it helps!
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this is the answer of math
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