Question

if the equation x-2y=3 and 3x+ky=1 have unique solution then k​

Answer 1

Step by step solution:-

a1÷a2 not equal to b1÷b2

1÷3 not equal to -2÷k

k is not equal to -6

Answer 2

$\huge\bold{\underline{Correct\:question:}}$

If the equation x-2y=3 and 3x+ky=1 have unique solution then find the value of K

$\huge\bold{\underline{Answer:}}$

◆ Given:

• x-2y=3
• 3x+ky=1

◆ To find:

Find the value of k

◆ Solution:

We have,

x-2y=3 and 3x+ky=1

The system of equations will have unique solution

Then, the lines are intersecting.

So,

$\bf{:\implies \dfrac{a_{1}}{a_{2}} ≠ \dfrac{b_{1}}{b_{2}}}$

$\bf{:\implies \dfrac{1}{3}≠\dfrac{-2}{k}}$

$\boxed{\bf{\pink{⟹\:k\:≠\:-6}}}$

So, the value of k is {k:k∈ R,k≠ -6}

Hence,this is the answer.

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