Question

if the equation x^3-ax^2+bx+c=0 has three real roots then which of the following is true? a) a=1 b)a is not equal to 1 c)b=1 d)b is not equal to 1

Answer 1

Answer:

For above question:

x3−ax2+bx−a=0x3−ax2+bx−a=0

x2∗(x−a)+(bx−a)=0x2∗(x−a)+(bx−a)=0

We are told that this equation has THREE roots. If look closer we notice that when b=1b=1 we can write the equation as:

x2∗(x−a)+(x−a)=0x2∗(x−a)+(x−a)=0 --> (x2+1)∗(x−a)=0(x2+1)∗(x−a)=0 and this equation has only ONE root x=ax=a.

Hence given equation to have three roots b must not equal to 1.

Step-by-step explanation:

#Be Brianly

Answer 2

Answer:

For above question:

x3−ax2+bx−a=0x3−ax2+bx−a=0

x2∗(x−a)+(bx−a)=0x2∗(x−a)+(bx−a)=0

We are told that this equation has THREE roots. If look closer we notice that when b=1b=1 we can write the equation as:

x2∗(x−a)+(x−a)=0x2∗(x−a)+(x−a)=0 --> (x2+1)∗(x−a)=0(x2+1)∗(x−a)=0 and this equation has only ONE root x=ax=a.

Hence given equation to have three roots b must not equal to 1.

Step-by-step explanation:

#Be Brianly