Question

if the equation x2-(2k+2)x+7k+1=0 has repeated real roots, find the value of k.

Answer 1

SInce repeated real roots,
Discriminant = 0
i.e, b²-4ac=0
where b= -(2k+2)
a=1
c= 7k+1

PLZ RATE IT AS BRAINLIEST

Answer 2

Answer:

Step-by-step explanation:

b²-4ac= 0

4k²+4+8k-28k-4=0

4k²-20k=0

4k(k-5)=0

k=5 or 0