if the equation x2-(2k+2)x+7k+1=0 has repeated real roots, find the value of k.
Answers
Answered by
8
SInce repeated real roots,
Discriminant = 0
i.e, b²-4ac=0
where b= -(2k+2)
a=1
c= 7k+1
PLZ RATE IT AS BRAINLIEST
Discriminant = 0
i.e, b²-4ac=0
where b= -(2k+2)
a=1
c= 7k+1
PLZ RATE IT AS BRAINLIEST
Answered by
2
Answer:
Step-by-step explanation:
b²-4ac= 0
4k²+4+8k-28k-4=0
4k²-20k=0
4k(k-5)=0
k=5 or 0
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