Question

if the equation x²-4x+a=0 has no real roots, then

$1.a < 4 \\2. a \leqslant 4 \\3. a < 2 \\4. a > 4$
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Answer 1

Answer:

4. is the correct option

Step-by-step explanation:

x^2-4x+a = 0

Comparing with ax^2 + bx + c= 0

a = 1 b = -4. c= a

b^2 -4ac < 0. ..equation has no real roots

(-4)^2 - 4(1)(a) < 0

16 -4a < 0

16 < 4a

4< a

a > 4