if the equation x2+ 4x+ k=0 has real and distinct roots, then find the values of k.
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Answer:
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Step-by-step explanation:
The given quadratic equation is
x^2+4x+k=0
A quadratic equation ax^2+bx+c=0 has real roots if
b^2-4ac\geq 0
We have,
a=1,b=4,c=k
(4)^2-4(1)(k)\geq 0
16-4k\geq 0
16\geq 4k
Divide both sides by 4.
4\geq k
Therefore the value of k must be less than or equal to 4.
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