Question

if the equation x²+4x+k =0 has real and distinct roots then
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Answer 1

Answer:

$b { }^{2} - 4ac = 0$

Step-by-step explanation:

here a=1,b=4,c=k

Here a=1,b=4,c=k

4×4-4×1×k=0

16-4k=0

16=4k

16÷4=k

k=6

There fore it has real and distict root