Question

If the equation x2 - ax + 1 = 0 has two distinct roots, then

[1 mark]
|a| = 2
|a| < 2
|a| > 2
None of these

Answer 1

Step-by-step explanation:

I think the answer is none of these not exactly

Answer 2

Solution :-

given

${x}^{2} - ax + 1 = 0 \\ here \\ a = x, \: b = - a ,\: c = 1 \\ \\ If \: the \: roots \: are \: distinct \: then \: \\ \\ {b}^{2} - 4ac > 0 \\ \\ \implies{( - a)}^{2} - 4 \times 1 \times 1 \\ \\ \implies \: a = 2$