if the equation x2-bx +1 =0 has two distinct real roots then which of the following is correct
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Answer:
Step-by-step explanation:
The given equation is x²-bx+1=0
The given equation has distinct and real roots.
So b²-4×1×1>0
=>b²-4>0
=> b²>4
=> b>√4 or b<-√4
=> b>2 or b<-2.
Hope you got it.
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