If the equation x²-bx+1=0 has two distinct real roots then
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Step-by-step explanation:
Given equation is x2−bx+1=0
If the equation doesnot possess real roots,then
b2−4ax<0
=>(−b)2−4(1)(1)<0
=>b2<4
=>b<±2
∴−2<b<2
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