Question

If the equation x2 – kx + 1, have no real roots, then

Answer 1

Answer:

k< 2

Step-by-step explanation:

tha quadratic equation which have no rwal root , the condition is given as

${b ^{2} - 4ac } < 0$

Answer 2

If the equation $x^2-kx+1$, have no real roots, then $k<\pm 2$

Step-by-step explanation:

To find : If the equation $x^2-kx+1$, have no real roots, then?

Solution :

We know that,

If quadratic equation have no real roots then discriminant is less than zero.

$D=b^2-4ac<0$

Here, a=1, b=-k and c=1

$(-k)^2-4(1)(1)<0$

$k^2-4<0$

$k^2<4$

$k<\sqrt{4}$

$k<\pm 2$

Therefore, If the equation $x^2-kx+1$, have no real roots, then $k<\pm 2$

#Learn more

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