Question

If the equation x² - kx + 9 = 0 does not posses real roots, then
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Answer 1

Answer:

If the equation x² - kx + 9 = 0 does not posses real roots, then D<0

b^2 -4ac < 0

K^2 - 4×1×9 < 0

K^2 - 36 < 0

K^2 < 36

k < ± 6

so k< +6

k > -6 ( as -6 is lesser than 0)

-6 < k < +6