Question

If the equation x2 – mx + 1 = 0 has two real and equal roots , then find the value of m.​

Answer 1

Answer:

$m=$ ± $2$

Step-by-step explanation:

For real and equal roots the discriminant of equation is equal to zero.

The equation is -

$x^2-mx+1=0$

Putting discriminant of above equation equal to zero -

$(-m)^2-4(1)(1)=0$

⇒$m^2-4=0$

⇒$m^2=4$

⇒$m=$ ±$\sqrt{4}$

⇒$m=$ ± $2$ .

Answer 2

Answer:

±2

Step-by-step explanation:

For equal and real roots we have to take D=0.

• x²-mx+1=0

• a=1, b=-m and c=1

• D= b²-4ac

• 0= -m² - 4(1)(1)

• 0= m²- 4

• 4= m²

• ±√4= m

• ± 2 = m