Question

If the equationlog12((log8(log4 x))/ log4(log4(logy ( log2 x ))))) = 0 has a solution for 'X' when c<y<b where y is not equal to a,where 'b is as large as possible and 'c' is as small as possible, then the value of(a + b + c) is equal to​

Answer 1

Answer:

the equationlog12((log8(log4 x))/ log4(log4(logy ( log2 x ))))) = 0 has a solution for 'X' when c<y<b where y is not equal to a,where 'b is as large as possible and 'c' is as small as possible, then the value of(a + b + c) is equal to

Answer 2

Answer:

Answer is 19

Step-by-step explanation:

For the equation to be zero

log12((log8(log4 x)) = 0

log8(log4(x))=1

log4(x)=8

log2(x) = 16

Put the value of log2(x) in denominator which cannot be zero

Therefore ;

log4(log4(logy16) is not equal to 0

on solving y is not equal to 2

So , a=2

since y = [2,15]

c=2 and b=15

a+b+c = 2 + 2 + 15

= 19 (Ans)