If the equations 2x^2-7x+3=0 and 4x^2+ax-3=0 have a common root them what is value of a
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Answered by
7
Answer:
-11
Step-by-step explanation:
Let the roots of the equation be x1 and x2
By factorizing 2x^2 - 7x + 3 = 0
2x^2 - 6x - x +3 = 0
2x ( x-3) -1 ( x-3) =0
(2x-1)(x-3)
x1 = 2x-1 =0 x2 = x-3 = 0
= x = 1/2 = x = 3
It it given that roots of both the equation are same so, if we put the value of "x" from above equation it should be equal to 0
Putting value of x = 3
4x^2 + ax -3 =0
4(3)^2 + 3x - 3 = 0
36 -3 + 3x = 0
3x = -33
(x = -11) Ans...
Hope it will help....
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