if the equations 4x-5y+14 and 5x-4y+13 are simultaneously true, then x-y=?
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Step-by-step explanation:
GIVEN: 4X-5Y+14=5X-4Y+13
FIRST REDUCING THE NON-APLHABETICAL NUMBERS
=> 4X-5Y+1=5X-4Y
=> MAKING X EQUAL:LCM:20
=> 5(4X-5Y+1)=4(5X-4Y)
=>20X-25Y+5 = 20X-16Y
CANCELLING 20X ON BOTH SIDES
=> -25Y+5=(-16Y)= -25Y+16Y= 5
=> -9Y = 5
NOW SATISFYING EQUATION IF 9Y = -5
MAKING Y EQUAL NOW
4(4X-5Y+1)=5(5X-4Y)
16X-20Y+1=25X-20Y
CANCELLING -20Y ON BOTH SIDEZ
16X+1=25X
25X-16X=1
9X=1
NOW BOTH VALUES X=1/9 AND Y = -5/9
OUR EQUATION = 1/9 - -5/9
=> 1/9+5/9 = 6/9 = 2/3 IN FRACTION FORM OR 0.66 IN DECIMAL FORM
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