Question

if the equations x^2+px+q=0 and x^2+qx+p=0 and p is not equal to q then what is the relationship between p and q

Answer 1

Answer:

q=-(1+p)

Step-by-step explanation:

x^2+px+q=0------------->(i)

x^2+qx+p=0------------->(ii)

(i)-(ii)

(x^2+px+q)-(x^2+qx+p) =0

Or, px+q-qx-p=0

Or, x={p-q}/{p-q}

Or, x=1

now putting the value of x in the equation (i) we get,

1^2+1*p+q=0

Or, 1+p+q=0

Or, q=-(1+p)