if the equations X square + a x + B C is equal to zero and X square + bx + c is equal to zero have a common root then there are other routes that satisfy the equation is
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Answer:
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Step-by-step explanation:
For quadratic equation ax
2
+bx+c=0
Sum of roots =−
a
b
Product of roots =
a
c
Let x
2
+ax+bc=0 have roots α and β:
α+β=−a......................(1)
αβ=bc...................(2)
Let x
2
+bx+ac=0 have roots α and γ:
α+γ=−b..................(3)
αγ=ac..................(4)
Subtracting (3) from (1) ,we get
β−γ=b−a..................(5)
Dividing (2) and (3)
γ
β
=
a
b
.................(6)
From (5) and (6)
β=b,γ=a
From (2)
α.b=bc⇒α=c
Now, equation having other roots is
x
2
−(β+γ)x+βγ=0
x
2
−(a+b)x+ab..................(7)
Since, β=b is the root of x
2
+ax+bc=0
⇒b
2
+ab+bc=0⇒a+b=−c
Putting this in (7)
we get x
2
+cx+ab=0
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