Question

if the equilibrium constant for the reaction 0.125. P4 +6Cl2 4PCl3 the value of equilibrium for this reaction?​

Answer 1

Answer:

The equilibrium: P4(g) + 6Cl2(g) 4PCl3(g) t = 0 1 1 0 t = teqm. 1 - α 1 - 6α 4α is attained by mixing equal moles (take 1 moles of each) of P4 and Cl2

Answer 2

The value of equilbrium constant for the reaction is 8

Explanation:

• The reaction for the formation of Phosphorous trichloride is as follows-

    $P4 +6Cl2 ---- 4PCl3$

• The equilibrium constant for the forward reaction will be given by the following formula

    $K_{c1} =\frac{[PCl3]^{4} }{[P_{4}][Cl_{2}] ^{6} }$

• the equilibrium constant for the reaction $k_{c1} = 0.125$

     $4PCl3------P4 +6Cl2$

• The equilibrium constant for the backward reaction will be given by following formula

       $K_{c2} = \frac{[P_{4}][Cl_{2}] ^{6} }{[PCl3]^{4}}$

• The relation between the equilibrium constant for forward reaction and backward reaction is related by the equation as follows

         $k_{c2}=\frac{1}{k_{c1} }$

• Substituting the value of equilibrium constant of forward reaction as given in the numerical

       $k_{c2}=\frac{1}{0.125}$

• On calculating the value we get the value of the equilibrium constant as

       $k_{c2}= 8$

• The value of equilibrium constant for the reaction is 8