Question

. If the % error in calculating the radius of a sphere is 2%, what will be the percentage error in calculating the volume? *

Answer 1

Answer:

As error in radius is 2 percent

u knw that volume of sphere =4/3πr3

in errors whether its on numerator side or denomitor it has to add

powers are simply multiplied

as it r3 it will b 3×R ie 3×2= 6 percent