if the error in the measurement if diameter of a circular disc is 1% then the error in the measurement of its surface area will be??
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Answer:
Ans is 2%
Explanation:
as we know total surface area=2×pie×r^2
I.e)2×pie×(D/2)^2
now apply log
log A=log(pie/2) + 2log D
now differentiate w.r.t dD
(dA/dD)×1/A=2/D
now rearranging we get
dA/A=2dD/D
so change=1×2=2%
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