Question

If the error in the measurement of radius is 2%, then the error in the determination of volume of the sphere will be
a) 8%
b) 2%
d) 6%
c) 4%
​

Answer 1

Answer:

d) 6%

Given :

• If the error in the measurement of radius is 2%

To find :

• the error in the determination of volume of the sphere

Solution :

v = 4/3πR³

in v = In(4/3π) + In R³

differentiating

dv/v = 3(dR/R)

error in the determination of the volume

= 3 x 2%

= 6%

Answer 2

ANSWER:-

$\color{red} {}➼OPTION (C) IS.. CORRECT$

➼volumn of sphere=4)3*πr³

➼∆v/v=3∆r/r%

➼3×2

➼6%

$\color{orange} {}➼AnSWeR$