If the error in the measurement of radius of a sphere
is 2%, then the error in the determination of volume
of the sphere will be
(a) 4 %
(b) 6 %
(c) 8 %
(d) 2 % (C.B.S.E. 2008)
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4
Answer:
V=4/3πR³
error in volume of sphere is 6%
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0
Answer:
Answer = error =6%
Explanation:
It is a correct.
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