Question

If the error in the measurement of radius of a sphere is 2%,
then the error in the determination of volume of the sphere
will be-
(Al2% (B)4% (C)6% (D)8%​

Answer 1

Answer:

Correct option - C

See below.

Explanation:

The volume of the sphere is,

$= \frac{4}{3} \pi r^3$

The radius is raised to the power of 3. We know,

When errors are raised to a power of k, then the error in the resulting quantity is k times the relative error.

The relative error ( percentage error ) is 2%. Therefore, we multiply 3 to 2% which yields 6%.

Therefore, the correct option is C.