Question

If the error in the measurement of radius of a sphere is 2%, then the error in the determination of the

volume of the sphere will be​

Answer 1

Answer:

0.6%

Explanation:

Error in measurement of radius = 2 %

Now,

Volume of sphere = $\frac{4}{3} \pi r^{3}$

Error in Volume = $\frac{1}{3} r$ = 2/3r = 0.6 %