Question

If the error in the measurement of surface area of sphere is 9%. Then the error in the measurement of volume of sphere will be ?​

Answer 1

Answer:

$\underline{\purple{\ddot{\MasterRohith}}}$

Given:-

• If the errors in the measurement of surface area of sphere is 9% .

To find :-

• The measurement of volume of sphere .

Explanation :-

• Here we know the formula ,

• delta V/ V= 3×delta R/R. Here volume contains r^3
• Therefore,
• Volume of sphere =3×9=27%.

Hope it helps u @ParthYadav.

Thank you .

Answer 2

Answer:

$\huge\color{blue}\boxed{\colorbox{lightgreen}{♧Given♧}}\bigstar$

• If the errors in the measurement of surface area of sphere is 9% .

$\huge\tt\red{❥}\tt\pink{T}\tt\blue{O} \ \ \tt\green{F}\tt\purple{I}\tt\orange{N}\tt\orange{D}\huge\tt\purple{｡✿}❥$

• The measurement of volume of sphere .

Explanation :-

• Here we know the formula ,

$δ \frac{V}{V} = 3 \times δ \: \frac{R}{R}$

$Here \: Volume \: contains \: r^3$

• Volume of sphere =3×9=27%.

$= > \mathfrak\pink{Volume \: of \: sphere = 27}$