Physics, asked by ngangbamibotomcha779, 1 day ago

if the error in the measurements of radius of a shpere is 2% then find the error in the determination of the volume of the sphere

Answers

Answered by Dhanush1236

0

Answer:

6%

Explanation:

Given, error in measuring radius = 2%

ie. Δr/r ×100=2 %

We know, volume of a sphere = 4πr^3/3

Percentage error in Volume = ΔV/V × 100 = 3 × Δr/r ×100 = 3 × 2 = 6%

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