Question

if the error in the measurements of the radius2% the the error in the measurements of the volume of the sphere​

Answer 1

Solution :

➡ Given:

✏ The error in the measurements of the radius is 2%

➡ To Find:

✏ The error in measurement of the volume of sphere.

➡ Formula:

✏ Volume of sphere is given by

$\star \: \underline{ \boxed{ \bold{ \rm{ \pink{volume = \frac{4}{3} \pi {r}^{3}}}}}}$

➡Calculation:

✏ Maximum error in measurement of volume of sphere is given by

$\implies \rm \: \% \frac{ \triangle{V}}{V} = 3(\% \frac{ \triangle{r}}{r} ) \\ \\ \therefore \rm \: \% \frac{ \triangle{V}}{V} = 3(2\%) \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \orange{\% \frac{ \triangle{V}}{V} = 6\%}}}}}$