Question

If the escape velocity from the surface of earth
is ve and velocity of a satellite revolving near
the surface of earth is v then- IMPPMT-97]
(1) v= V2v (2) v. = 2v
(3) ve = V2v
(4) ve ² √2v​

Answer 1

Answer:

ve=√2(v)

option 3 is the correct answer

Explanation:

given ,

escape velocity is ve

ve=√(2GM/R)

orbital velocity is v

v=√(GM/R)

therefore ve=√2(v)