Question

if the expansion (4a-8x)^1÷2 were to possible then​

Answer 1

|$\frac{a}{x}$| > 2

Step-by-step explanation:

Given,

$(4a-8x)^{1/2}$

= 4a$( 1 - 2x/a)^{1/2}$

As we know, if

(1 + x)^p

where p is a fractional power, then for expansion to exist and coincide |x| must be less than 1.

|x| < 1

Thus,

|$\frac{2x}{a}$| < 1

|$\frac{x}{a}$|  < 1/2

or

|$\frac{a}{x}$| > 2

Therefore, option A i.e. |$\frac{a}{x}$| > 2 is the correct answer.

Learn more: Expansion

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