Question

If the expression (k^2 - 2k + 1)y + √17 is a constant polynomial, then find the value of k.


With proper steps please....​

Answer 1

coefficient of y = 0 for constant

k^2 - 2k +1=0

k-1)^2 = 0

k= 1

Answer 2

coefficient of y = 0

y is a constant then

we find value of k

we have

k^2 - 2k +1=0

(k-1)^2 = 0

k= 1

I hope it help u