Question

If the expression (mx-1+1/2) is always non-negative, then the minimum value of m must be.....​

Answer 1

Answer:

hope you get your answer

Step-by-step explanation:

We have,mx-1+1x≥0 ∀x∈R+

As, non-negative means greater than or equal to 0

i.e.≥0⇒mx2-x+1x≥0⇒mx2-x+1≥0

This is only possible if m>0 and D≤0⇒-12-4m≤0⇒1≤4m⇒14≤m⇒m≥14

So, the minimum value of m must be equal to 14.

Answer 2

Answer:

Minimum value of m must be 14.