If the expression y = 8x - x² - 15 is negative then complete x lies in the interval
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Answered by
0
Answer:
x
2
−5x−14>0
x
2
−7x+2x−14>0
(x−7)(x+2)>0
⇒x<−2 or x>7
Hence for x∈(−∞,−2)∪(2,∞), the expression x
2
−5x−14 is positive.
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Answered by
0
Answer:
y-(8*x-x^2-15)=0
y + x2 - 8x + 15 = 0
Solve y+x2-8x+15 = 0
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
We shall not handle this type of equations at this time.
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