If the exterior ∠ACD of ΔABC has the measure 120 and one of two internal opposite angles has the measure 40, then find the measures of the remaining angles of ΔABC.
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Let angles of triangle be A, B, C
We know that by exterior angle property
angle ACD=B+C
Given that, B=40
Then by property
120=40+C
C=80
By angle sum property
A+B+C=180
A+40+80=180
A+120=180
A=180-120
A=60
I hope this is helpful
We know that by exterior angle property
angle ACD=B+C
Given that, B=40
Then by property
120=40+C
C=80
By angle sum property
A+B+C=180
A+40+80=180
A+120=180
A=180-120
A=60
I hope this is helpful
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