if the exterior angles of a pentagon are x•,(x+5)•,(x+10)•,(x+15)•,(x+20)•,find the value of x
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Total exterior angles of a polygon=
360°
x°+(x+5)°+(x+10)°+(x+15)°+(x+20)°=360°
x+x+5+x+10+x+15+x+20=360° (Removing the brackets)
x+x+x+x+x+5+10+15+20=360°
5x+50=360°
5x=360-50
5x=310°
x=310/5
x=62°
x=62°
x=62+5=57°
x=62+10=72°
x=62+15=77°
x=62+20=82°
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